Integrand size = 18, antiderivative size = 45 \[ \int \sqrt {-1+x} x^2 \sqrt {1+x} \, dx=\frac {1}{8} \sqrt {-1+x} x \sqrt {1+x}+\frac {1}{4} (-1+x)^{3/2} x (1+x)^{3/2}-\frac {\text {arccosh}(x)}{8} \]
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Time = 0.00 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {92, 38, 54} \[ \int \sqrt {-1+x} x^2 \sqrt {1+x} \, dx=-\frac {\text {arccosh}(x)}{8}+\frac {1}{4} (x-1)^{3/2} x (x+1)^{3/2}+\frac {1}{8} \sqrt {x-1} x \sqrt {x+1} \]
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Rule 38
Rule 54
Rule 92
Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} (-1+x)^{3/2} x (1+x)^{3/2}+\frac {1}{4} \int \sqrt {-1+x} \sqrt {1+x} \, dx \\ & = \frac {1}{8} \sqrt {-1+x} x \sqrt {1+x}+\frac {1}{4} (-1+x)^{3/2} x (1+x)^{3/2}-\frac {1}{8} \int \frac {1}{\sqrt {-1+x} \sqrt {1+x}} \, dx \\ & = \frac {1}{8} \sqrt {-1+x} x \sqrt {1+x}+\frac {1}{4} (-1+x)^{3/2} x (1+x)^{3/2}-\frac {1}{8} \cosh ^{-1}(x) \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.13 \[ \int \sqrt {-1+x} x^2 \sqrt {1+x} \, dx=\frac {1}{8} \left (x \sqrt {\frac {-1+x}{1+x}} \left (-1-x+2 x^2+2 x^3\right )-2 \text {arctanh}\left (\sqrt {\frac {-1+x}{1+x}}\right )\right ) \]
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Time = 1.45 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.16
method | result | size |
default | \(-\frac {\sqrt {-1+x}\, \sqrt {1+x}\, \left (-2 x^{3} \sqrt {x^{2}-1}+x \sqrt {x^{2}-1}+\ln \left (x +\sqrt {x^{2}-1}\right )\right )}{8 \sqrt {x^{2}-1}}\) | \(52\) |
risch | \(\frac {x \left (2 x^{2}-1\right ) \sqrt {-1+x}\, \sqrt {1+x}}{8}-\frac {\ln \left (x +\sqrt {x^{2}-1}\right ) \sqrt {\left (-1+x \right ) \left (1+x \right )}}{8 \sqrt {-1+x}\, \sqrt {1+x}}\) | \(53\) |
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Time = 0.23 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.89 \[ \int \sqrt {-1+x} x^2 \sqrt {1+x} \, dx=\frac {1}{8} \, {\left (2 \, x^{3} - x\right )} \sqrt {x + 1} \sqrt {x - 1} + \frac {1}{8} \, \log \left (\sqrt {x + 1} \sqrt {x - 1} - x\right ) \]
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\[ \int \sqrt {-1+x} x^2 \sqrt {1+x} \, dx=\int x^{2} \sqrt {x - 1} \sqrt {x + 1}\, dx \]
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Time = 0.20 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.82 \[ \int \sqrt {-1+x} x^2 \sqrt {1+x} \, dx=\frac {1}{4} \, {\left (x^{2} - 1\right )}^{\frac {3}{2}} x + \frac {1}{8} \, \sqrt {x^{2} - 1} x - \frac {1}{8} \, \log \left (2 \, x + 2 \, \sqrt {x^{2} - 1}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 70 vs. \(2 (31) = 62\).
Time = 0.29 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.56 \[ \int \sqrt {-1+x} x^2 \sqrt {1+x} \, dx=\frac {1}{24} \, {\left ({\left (2 \, {\left (3 \, x - 10\right )} {\left (x + 1\right )} + 43\right )} {\left (x + 1\right )} - 39\right )} \sqrt {x + 1} \sqrt {x - 1} + \frac {1}{6} \, {\left ({\left (2 \, x - 5\right )} {\left (x + 1\right )} + 9\right )} \sqrt {x + 1} \sqrt {x - 1} + \frac {1}{4} \, \log \left (\sqrt {x + 1} - \sqrt {x - 1}\right ) \]
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Time = 7.72 (sec) , antiderivative size = 362, normalized size of antiderivative = 8.04 \[ \int \sqrt {-1+x} x^2 \sqrt {1+x} \, dx=-\frac {\mathrm {atanh}\left (\frac {\sqrt {x-1}-\mathrm {i}}{\sqrt {x+1}-1}\right )}{2}+\frac {\frac {35\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^3}{2\,{\left (\sqrt {x+1}-1\right )}^3}+\frac {273\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^5}{2\,{\left (\sqrt {x+1}-1\right )}^5}+\frac {715\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^7}{2\,{\left (\sqrt {x+1}-1\right )}^7}+\frac {715\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^9}{2\,{\left (\sqrt {x+1}-1\right )}^9}+\frac {273\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^{11}}{2\,{\left (\sqrt {x+1}-1\right )}^{11}}+\frac {35\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^{13}}{2\,{\left (\sqrt {x+1}-1\right )}^{13}}+\frac {{\left (\sqrt {x-1}-\mathrm {i}\right )}^{15}}{2\,{\left (\sqrt {x+1}-1\right )}^{15}}+\frac {\sqrt {x-1}-\mathrm {i}}{2\,\left (\sqrt {x+1}-1\right )}}{1+\frac {28\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^4}{{\left (\sqrt {x+1}-1\right )}^4}-\frac {56\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^6}{{\left (\sqrt {x+1}-1\right )}^6}+\frac {70\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^8}{{\left (\sqrt {x+1}-1\right )}^8}-\frac {56\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^{10}}{{\left (\sqrt {x+1}-1\right )}^{10}}+\frac {28\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^{12}}{{\left (\sqrt {x+1}-1\right )}^{12}}-\frac {8\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^{14}}{{\left (\sqrt {x+1}-1\right )}^{14}}+\frac {{\left (\sqrt {x-1}-\mathrm {i}\right )}^{16}}{{\left (\sqrt {x+1}-1\right )}^{16}}-\frac {8\,{\left (\sqrt {x-1}-\mathrm {i}\right )}^2}{{\left (\sqrt {x+1}-1\right )}^2}} \]
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